Monte

"Throbbing Corporate Pain" is my new favorite (fictional) band name.

If you can solve this, you’re a true mathematician. Most people get it wrong. e^(iπ) + 1

If you can solve this WITHOUT a calculator, you’re a true genius. Most people get it wrong. >f(x)=3x+1/2^v2(3x+1)> Drop your final answer below. v2(n) is the number of times you can divide n by 2 before it becomes odd. If you know that, you already know what this function does.

Anybody know of any B-Movie production houses that accept concepts? I've got some hilarious ones. Maybe @theasylumcc? Or @Cineverse_ent?

Hey @untsfc! Local creator here with a Noir concept for Fall 2026. Just sent a detailed collab offer to your Gmail. Looking for a student director/writer partner!

If @BrandonAubrey17 wants $10 million a year, I don't see the problem. Write the check @dallascowboys.

I think it's hilarious that some people are now talking about "Free Range Parenting" as if it's something new. I'm GenX, and we're like, "Yeah, we already did that..."

Old Rose remembering the last time the @dallascowboys won a Super Bowl:

Hi @FedEx @FedExHelp just wondering why my package got delayed from yesterday to today, and now why the delivery timeframe changed from an actual time to "by end of day". It's not going to get delayed again, is it?

Ran Collatz on every odd N ≤ 10^12. 49,999,999 odd starting numbers. N=3 → 1 is the *weakest* path. Net LNR = -ln 3. No other gets close. Zero in (-ln 3, 0). Not a proof. Just what I saw. Could this rule out non-trivial cycles or divergence? #Collatz #Math

🚨 COLLATZ PROVEN SYMBOLICALLY 🚨 ai.vixra.org/abs/2510.0047 : → All n from 1 via inverse motifs → Reverse path = bijection → QED → No cycles/divergence → 100M tests + induction @MathUGA @umichMath @TexasScience @MITMath @TAMUArtSci @SMUMathematics #Collatz

🚨 COLLATZ PROVEN SYMBOLICALLY 🚨 viXra 2510.0047 (6p): → Every n from 1 via inverse motifs → Reverse path = bijection → QED → No cycles/divergence → 100M tests + induction ai.vixra.org/abs/2510.0047 @terrytao @jefflagarias @scottaaronson #Collatz

Collatz proof? ai.vixra.org/abs/2510.0047 or drive.google.com/file/d/1PXr… Bijection (O⁻¹ follows E⁻ᵏ, smallest k), 100M tests, n=3: O E O E⁴. Thoughts? @QuantaMagazine @MITMath @HarvardMath @numbertheory #Collatz

My symbolic grammar solves Collatz: 100M numbers → 1, no cycles. n=100M in 59 steps: ai.vixra.org/abs/2510.0047. Break it...if you can! @MathOverflow @numbertheory #Collatz

I know Collatz attracts wild claims. This isn’t one. I built a symbolic grammar that deterministically reaches every number up to 100 million. It’s public. It’s rigorous. It’s open for scrutiny. See for yourself: ai.vixra.org/abs/2510.0047 #Collatz

Thanks for the views from @SMUMathematics! Collatz proof: ai.viXra.org/2510.0047. Motif bijection maps ℤ⁺ to 1, 100M tests, no cycles. n=3: O E1 O E4 ↔ inverse. Feedback? #Collatz

Resolved Collatz via motif bijection? Inverse grammar generates all ℤ⁺ from 1. 100M unique sequences, no collisions. n=99998143 (152 motifs, longest), n=99970624 (22 motifs, short). AI phrasing assist; math original. Google Docs: drive.google.com/file/d/1PXr…. #Collatz #MathTwitter